Determining if a year is a leap year is a common task in programming. In C++, you can use the std::chrono::year class from the C++ Standard Library to simplify this check. Here’s an example of how to accomplish this:

#include <iostream>
#include <chrono>

bool isLeapYear(int year) {
    std::chrono::year y{ year };
    return y.is_leap();
}

int main() {
    int year;
    std::cout << "Enter a year: ";
    std::cin >> year;

    if (isLeapYear(year)) {
        std::cout << year << " is a leap year." << std::endl;
    } else {
        std::cout << year << " is not a leap year." << std::endl;
    }

    return 0;
}

In this example, we define a function isLeapYear that takes an int parameter representing the year to check. Inside the function, we create a std::chrono::year object using the input year. Then, we use the is_leap() member function to determine if the year is a leap year. The function returns true if it is a leap year and false otherwise.

In the main function, we prompt the user to enter a year, read it from the standard input, and call the isLeapYear function. Based on the return value, we display whether the year is a leap year or not.

Now you can easily check if a year is a leap year using the C++ Standard Library and std::chrono::year class!