Let’s assume we have two 2D vectors, vector1
and vector2
, both of the same size. Our goal is to copy the elements from vector1
into vector2
so that both vectors contain the same values.
Here’s a simple and efficient way to achieve this:
vector1 = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]
vector2 = [[] for _ in range(len(vector1))]
for i in range(len(vector1)):
vector2[i] = vector1[i][:]
In the above code snippet, we first initialize an empty vector2
by using a list comprehension. The size of vector2
is the same as vector1
, and each sub-list is initially empty.
Next, we iterate over the indices of vector1
using a for
loop. Inside the loop, we use the slice notation vector1[i][:]
to create a copy of the elements in vector1[i]
. This ensures that modifying vector2
later won’t affect vector1
.
After running this code, vector2
will contain the same elements as vector1
. It’s important to note that this method works correctly for any 2D vector, irrespective of its size or the values stored within it.
Using this technique, you can easily copy the contents of one 2D vector to another in Python.
#python #vector