To perform a logical AND operation between multiple bitsets, we can use the & operator. Here’s an example that demonstrates how to do this:

#include <bitset>
#include <iostream>

int main() {
  std::bitset<8> bitset1("10101010");
  std::bitset<8> bitset2("01100110");
  std::bitset<8> bitset3("11110000");

  std::bitset<8> result = bitset1 & bitset2 & bitset3;

  std::cout << "Result: " << result << std::endl;

  return 0;
}

In the code above, we define three bitsets (bitset1, bitset2, and bitset3) and initialize them with binary strings. We then perform the logical AND operation between these bitsets using the & operator and store the result in the result variable.

Finally, we print the value of the result bitset, which will be the logical AND of all three original bitsets.

The output of the above code will be:

Result: 00100000

As you can see, the result bitset contains the position of the bits that are set to 1 in all three original bitsets.

In summary, applying a logical AND between multiple bitsets in C++ can be easily achieved using the & operator. This allows us to perform various bitwise operations efficiently and effectively when working with sets of bits in our code.

#C++ #BitwiseOperators