To find the intersection of two bitsets, we can use the bitwise AND operator. This operator performs a logical AND operation on each corresponding pair of bits from the two bitsets. The result is a new bitset where each bit is set to 1 if both corresponding bits in the input bitsets are also 1.

Let’s take a look at an example:

#include <iostream>
#include <bitset>

int main() {
  std::bitset<8> bitset1("10101010");
  std::bitset<8> bitset2("11001100");

  std::bitset<8> intersection = bitset1 & bitset2;

  std::cout << "Intersection: " << intersection << std::endl;

  return 0;
}

In this example, we have two bitsets: bitset1 and bitset2 with 8 bits each. We have initialized bitset1 with the binary value “10101010” and bitset2 with “11001100”.

We then use the bitwise AND operator (&) to find the intersection of bitset1 and bitset2. The resulting bitset intersection will contain 1s only in the positions where both bitset1 and bitset2 have 1s.

When we run this code, the output will be:

Intersection: 10001000

In this case, the intersection of bitset1 and bitset2 is “10001000”.

By utilizing the bitwise AND operator, we can easily find the common bits between two bitsets. This approach can be extended to perform other set operations, such as union and difference, using different bitwise operators.

So, the next time you need to find the intersection of two C++ bitsets, give the bitwise AND operator a try. It’s a simple and efficient way to accomplish this task.

#cplusplus #bitsets